(x^2-3x+1)(4x+5)=

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Solution for (x^2-3x+1)(4x+5)= equation: 


Simplifying
(x2 + -3x + 1)(4x + 5) = 0

Reorder the terms:
(1 + -3x + x2)(4x + 5) = 0

Reorder the terms:
(1 + -3x + x2)(5 + 4x) = 0

Multiply (1 + -3x + x2) * (5 + 4x)
(1(5 + 4x) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
((5 * 1 + 4x * 1) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
((5 + 4x) + -3x * (5 + 4x) + x2(5 + 4x)) = 0
(5 + 4x + (5 * -3x + 4x * -3x) + x2(5 + 4x)) = 0
(5 + 4x + (-15x + -12x2) + x2(5 + 4x)) = 0
(5 + 4x + -15x + -12x2 + (5 * x2 + 4x * x2)) = 0
(5 + 4x + -15x + -12x2 + (5x2 + 4x3)) = 0

Combine like terms: 4x + -15x = -11x
(5 + -11x + -12x2 + 5x2 + 4x3) = 0

Combine like terms: -12x2 + 5x2 = -7x2
(5 + -11x + -7x2 + 4x3) = 0

Solving
5 + -11x + -7x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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